Menu

Physicshelpline

Solution Search

Comments

Coulomb's Law: Force and Field

Q- Two charges placed on the x axis. Qa = 4 µC at x = 0 and Qb = - 4 µC at x = 22cm.

(a) Find the net electric field at point P at x = - 6 cm. 

(b) Find the force on Qb due to Qa

(c) The charges Qa and Qb are now attached to the ends of a spring whose un-stretched length is s0 = 22 cm and released. With the charges attached, the spring compresses to an equilibrium length s1 = 12 cm. Calculate the spring constant ks of the spring. 

Solution:

Go Back

Comment