Menu

Physicshelpline

Solution Search

Comments

Electrostatics: Coulomb's Law

Q- A rigid, insulating fiber if fixed vertically. A charge Qa = -7 µC is fixed to the fiber at some point. A bead with a hole drilled through its center is slipped over the fiber above Qa and is free to move along the fiber without friction. The mass of the bead is m = 160 g and its charge is Qb. At equilibrium, the bead floats a distance yb = 16 cm above the Qa.

(a) Calculate the charge on the bead.

(b) If the mass of the bead were tripled (m' = 3m), how far above the origin would it now float at equilibrium?

(c) The bead (with original mass m) is removed and its charge altered to Qc. When placed on the fiber from below Qc, it floats at equilibrium point yc = -11 cm below the origin. What is this new charge?

Solution:

Go Back

Comment