Projectile Motion
Q 1 - A man standing 29 m from the base of a vertical cliff throws a ball with a speed of 38 m/s aimed directly at a point 6 m above the base of the cliff.
a) How long does it take the ball to reach the cliff?
b) Neglecting air resistance and the height of the man, calculate the height above the base of the cliff at which the ball hits.
c) How fast is the ball moving when it reaches the cliff?
d) At what time does the ball reach its largest vertical height?
e) At what horizontal distance from the man does the ball reach its largest vertical height?

Solution

Q2- A gun shoots bullets that leave the muzzle at 207 m/s. If a bullet is to hit a target 159.9 m away at the level of the muzzle, the gun must be aimed at a point above the target. (Neglect air resistance.)

How far above the target is this point if the angle the gun makes is less than 45^o.

Solution

Q3- A ball is thrown into the air from ground level. After a time t = 1 s, the ball has traveled to a position x₁ = 28 m to the right of and y₁ = 11 m up from where it was thrown (at this time, the x and y components of the ball's velocity are still positive). The axes show the x and y directions to be considered positive

1. What was the x component of the initial velocity of the ball?
2. What was the y component of the initial velocity of the ball?
3. What was the initial speed of the throw?
4. What was the initial angle of the throw relative to the horizontal?  
5. What is the height of the ball at the top of its path?

Solution